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post you are run length encoding in lisp

Name: Anonymous 2014-10-05 3:18

critique mine pl0x:

(defun rle (str) ;run length encoding
(let ((i 0) c count out)
(while (< i (length str))
(if (eq c (elt str i))
(setq count (1+ count))
(when c
(setq out (append out (list (cons c count)))))
(setq c (elt str i))
(setq count 1))
(setq i (1+ i)))
(when c (setq out (append out (list (cons c count)))))
out))

Name: Anonymous 2014-10-05 16:05

Symta version (based on Prolog one)
rle Xs =
| Ys = []
| while 1: case Xs [Z N%&Z @Zs] | [[N.size+1 Z] @!Ys]; Xs <= Zs
[Z @Zs] | [Z @!Ys]; Xs <= Zs
[] | leave Ys.flip
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