Random Algebra

Given functions
f(a,b) = random(a) < random(b)
and
g(a,b) = a < random(a+b)

which if of them is more likely to result into 1, if random(n) returns arbitrary number in range of [0;n)?

Justify your answer.

<anime> f(a,b) = random(a) < random(b) and g(a,b) = a < random(a+b)
<anime> how to prove they're equal?
<dalcde> anime: No one can help you until you make yourself comprehensible.
<anime> ok
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<FilipinosRich> dalcde what was the link again to your group theory notes
<FilipinosRich> If you don't mind me asking
<dalcde> dec41.user.srcf.net <---------- ### LEL hes a cambridge math toilet scrubber
<FilipinosRich> Thanks
<anime> dalcde, maybe if you had more than 2 IQ points to rub together you could figure it out ;)
<dalcde> This is ##math, not ##psychology.
<dalcde> We are not psychics.
<FilipinosRich> Lool
<xrlk> lol i hope you didnt spend 2 minutes brainstorming that comeback
<xrlk> hey Z-module got any SICK maths to teach me today????
<Svitkona> anime, what do you mean by "equal"
<Svitkona> what is random(a)
<anime> =
<xrlk> XD
<anime> it's a random number from 0 to a
<Svitkona> ok, what does f(a, b) = random(a) < random(b) mean
<anime> this is basic stuff dude
<xrlk> XD
<FilipinosRich> lmfao
<Svitkona> can you explain, then?
<anime> why act like this is confusing or hard
<xrlk> ebin trolle
<someone13> a chick once stabbed me

turns out /prog/ is smarter than cambridge math teachers, who knew?

<HisShadow_> anime: use voretion of cobenations
<anime> thanks HisShadow_, I'll try
<ayush1> did anyone find a simpler method for my problem?
<dalcde> HisShadow_: I think anime needs to compute the third derived cohomology group of the stochastic bundle instead.
<zehdeh> I have a set of points that resemble a sphere. I want a single value for every point telling me how much like a perfect sphere it actually is. Is curvature the right thing for this?
<anime> wow u must be so smart dalcde that sounded complicxed xD
<anime> i love pretending to be smart on the internet by talking about cohomology
<zehdeh> *in the area between the point and its neighbors
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<dalcde> anime: Nah you need to find something harder.
<anime> dalcde, omg you're like sheldon out of big bang theory :D
<dalcde> Cohomology is easy. It is just computing the connected components of the hom sets with the nth delooping of the representing object in an infinity-1 topos.
<dalcde> (That is actually true)
dalcde!*@* added to ignore list.
<Svitkona> anime, can you please explain?
<FilipinosRich> Was about to say that the easy part is relative
<anime> stop pinging me
<Svitkona> anime, do you want me to stop pinging you?
<Svitkona> anime, was that towards me?
<xrlk> anime,
<FilipinosRich> anime why
<xrlk> were u talking about me??
<ayush1> rain1