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A new floating point format

Name: Anonymous 2017-07-02 5:54

Can express numbers from ~ 2^(2^(10^-308)) to 2^(2^(10^308))
https://www.reddit.com/r/frozenvoid/wiki/algorithms/data_encoding/logfloat

Name: Anonymous 2017-07-03 15:37

>>16
1.0000000086*(e^1.09861228)=

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