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Pi Formula

Name: Anonymous 2018-10-08 21:55

Can you prove that
Pi = lim 2*(2^n / (n!/k!/(n/2)!))^2
[as n approaches infinity]


???

Name: Anonymous 2018-10-09 1:33

So nth_rt( n! / k!^2 ) = 2 * 1/nth_rt(sqrt(pi/2))?

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