What will this output?

What will this program output?
Good luck, you'll need it!

#include <iostream>
using namespace std;

int main() {
class c {
public:
c() {
void f();
f();
}
};

c my_c();
}

void f() {
cout << "VALID C++" << endl;
}

The answer is absolutely nothing because c my_c(); is a fucking function declaration.

>>84

We are not however.

[citation needed]

The standard does not contain the world ``segfault''.

It doesn't have to. This is an OS issue, not a C Standard issue. Regardless of what language your program is written in, accessing illegal memory is a segmentation fault.

Are you aware that 1 might not stand for EXIT_FAILURE on some implementations?

And I'm not assuming that it is. Neither EXIT_SUCCESS == 0 nor EXIT_FAILURE == 1 is guaranteed by the standard; however anything that isn't either EXIT_SUCCESS or 0 should be interpreted as indicating failure.

Again, many assumptions.

Those assumptions were chosen to simplify the discussion of the algorithm.