Its a trollpost for retards that believe that 0.999...=1 and that infinitesimals don't exist(spoiler: they are). They discard tiny infinitesimal segments at the edges.
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Anonymous2020-07-12 7:48
It's 2-sqrt(2) / sqrt(2)
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Anonymous2020-07-12 7:50
Lets call it a subset of the Inverse fractional dubs theory
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Anonymous2020-07-12 7:57
>>3 OP pic was borrowed from a trollish pi=4 thread, don't mind it too much
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Anonymous2020-07-12 8:32
It's in the same group as the golden ratio (-also an Inverse fractional dub)
They might be constructable too?
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Anonymous2020-07-12 8:45
0.302775637.. is an artificial one
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Anonymous2020-07-12 8:52
HOME BUTTON will take you to the top of the page. Do not need a floating blue arrow button that obscures the webpage content. You are welcome.
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Anonymous2020-07-12 8:54
Sort of continued fraction related maybe
x = 1/x +- some integer i
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Anonymous2020-07-12 8:58
Convergent fraction seems like a good description, but alas
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Anonymous2020-07-12 9:34
So anyway, how to factor in the .4142 to the (1,-1):(1,0) - slopedist(x)=sqrt(1+x^2)
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Anonymous2020-07-12 11:00
I have once wrote one in Symta. It worked the same way you trace fractals - by recursively descending to measure arc size. So in a sense a circle is a fractal too. Just a very round one.
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Anonymous2020-07-12 12:08
>>6 Both cases involve infinitesimal segments hidden by "close fit" scaling, which preserve specific non-pi perimeter,like (1-0.999...) scaled by N propositional to (1-1/10^N of 0.999...).
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Anonymous2020-07-12 12:36
>>13 It might have to branch to count, or probably at least change scale and direction
>>16 This is what 16-year-olds think ``based'' is.
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Anonymous2020-07-12 12:52
Not quite >0.5 (1 - 0.4142) / 0.5 1:1.1716
<0.5 (0.4142) / 0.5 1:0.8284
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Anonymous2020-07-12 13:01
*second order deriv?
These coordinates are pretty loose so it might work
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Anonymous2020-07-12 17:09
>>15 it rotate the vector by a/2 on each iteration, then re-normalized it and rotate again. No sin/cos are needed for 1/2 rotation starting from PI/2 angle
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Anonymous2020-07-12 17:11
>>20 BTW, one can also calculate sin and cos using the same algorithm.
And the "Pi" will be different if the function metric picked is not euclidean.
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Anonymous2020-07-12 17:11
>>21 In fact, I think for actual fractals PI can be infinite.