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I calculated the sides of a triangle from its medians

Name: Anonymous 2022-03-12 4:31

It gave

L_a = (2sqrt(2(m_bˆ2+m_cˆ2)-m_aˆ2))/3
L_b = (2sqrt(2(m_aˆ2+m_cˆ2)-m_bˆ2))/3
L_c = (2sqrt(2(m_bˆ2+m_aˆ2)-m_cˆ2))/3

Where L_a, L_b, L_c are the sides of the triangle opposite the vertices A, B, C, and m_a, m_b, m_c are the medians of the triangle connecting the vertices A, B, C to the midpoints of the sides L_a, L_b, L_c, respectively.

Name: Anonymous 2022-03-12 7:25

\(L_a = (2sqrt(2(m_b^2+m_c^2)-m_a^2))/3

L_b = (2sqrt(2(m_a^2+m_c^2)-m_b^2))/3
L_c = (2sqrt(2(m_b^2+m_a^2)-m_c^2))/3\)

how post math

Name: Anonymous 2022-03-12 18:42

>>2
\(L_a = \frac{2\sqrt{2(m_b^2+m_c^2)-m_a^2}}{3}\)

\(L_b = \frac{2\sqrt{2(m_a^2+m_c^2)-m_b^2}}{3}\)

\(L_c = \frac{2\sqrt{2(m_b^2+m_a^2)-m_c^2}}{3}\)

Name: Anonymous 2022-03-13 7:13

>>3
please drop documentation, thanxs!

Name: Anonymous 2022-03-13 13:22

What programming language is this?

Name: Anonymous 2022-03-13 16:36

>>5
Mathematics is very important for computer programming and computer science! Therefore, I think it is justified to post about it in this board.
>>4
I just exchanged sqrt(...) for \sqrt{...} in all instances and added \frac{...}{...} in place of (...)/(...).
Somehow I couldn't manage to make new lines (\newline doesn't work) so I used multiple math tags, one for each equation, with regular line breaks outside them between one another.

Name: Anonymous 2022-03-13 20:20

/prog/ - Middle School Math

Name: Anonymous 2022-03-13 20:38

>>6
Ah, so it is LaTeX-based, thanks!

Name: Anonymous 2022-03-14 6:13

\(\TeX > \LaTeX\)

Don't change these.
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