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Random Algebra

Name: Anonymous 2016-08-05 16:07

Given functions
f(a,b) = random(a) < random(b)
and
g(a,b) = a < random(a+b)

which if of them is more likely to result into 1, if random(n) returns arbitrary number in range of [0;n)?

Justify your answer.

Name: Anonymous 2016-08-07 12:00

>>38
so they're equal?

>>39
could you try being a bit more productive?

Name: Anonymous 2016-08-07 19:23

>>41
so they're equal?

Yes, I think it's definitely equal. random(a+b) is always some very small number (<1) above random(a)+random(b) but that's probably an artifact of the pseudorandom number generator.

Name: Anonymous 2016-08-07 19:26

Name: Anonymous 2016-08-07 20:47

>>43
int getRandomNumber()
{
Stopped reading there.

Name: Anonymous 2016-08-07 22:06

>>44
checkDubs();

Name: Anonymous 2016-08-08 1:23

<<37

for a>0 & b>0

p(F) = ((b*b) / 2) / (a*b) iif (a>=b)
1 - ((a*a) / 2) / (a*b) iif (a<=b)

Name: Anonymous 2016-08-08 2:10

0.5* b^2 / (a*b)
= b^2 / (2ab)
?= b / 2a

b / (a+b) - b / 2a

?= 2ab / 2a(a+b) - (a+b)b / (a+b)2a
= 2ab / 2(aa + ab) - (ab + bb) / 2(aa + bb)
= (2ab - (ab + bb)) / 2(aa + bb)
= (2ab - ab - bb) / (2aa + 2bb)
= (ab - bb) / (2aa + 2bb) [a >= b]

Name: Anonymous 2016-08-08 15:04

<anime> f(a,b) = random(a) < random(b) and g(a,b) = a < random(a+b)
<anime> how to prove they're equal?
<dalcde> anime: No one can help you until you make yourself comprehensible.
<anime> ok
* gfixler has quit (Ping timeout: 265 seconds)
* GoldenKey has quit (Read error: Connection reset by peer)
<FilipinosRich> dalcde what was the link again to your group theory notes
<FilipinosRich> If you don't mind me asking
<dalcde> dec41.user.srcf.net <---------- ### LEL hes a cambridge math toilet scrubber
<FilipinosRich> Thanks
<anime> dalcde, maybe if you had more than 2 IQ points to rub together you could figure it out ;)
<dalcde> This is ##math, not ##psychology.
<dalcde> We are not psychics.
<FilipinosRich> Lool
<xrlk> lol i hope you didnt spend 2 minutes brainstorming that comeback
<xrlk> hey Z-module got any SICK maths to teach me today????
<Svitkona> anime, what do you mean by "equal"
<Svitkona> what is random(a)
<anime> =
<xrlk> XD
<anime> it's a random number from 0 to a
<Svitkona> ok, what does f(a, b) = random(a) < random(b) mean
<anime> this is basic stuff dude
<xrlk> XD
<FilipinosRich> lmfao
<Svitkona> can you explain, then?
<anime> why act like this is confusing or hard
<xrlk> ebin trolle
<someone13> a chick once stabbed me


turns out /prog/ is smarter than cambridge math teachers, who knew?

Name: Anonymous 2016-08-08 15:13

<HisShadow_> anime: use voretion of cobenations
<anime> thanks HisShadow_, I'll try
<ayush1> did anyone find a simpler method for my problem?
<dalcde> HisShadow_: I think anime needs to compute the third derived cohomology group of the stochastic bundle instead.
<zehdeh> I have a set of points that resemble a sphere. I want a single value for every point telling me how much like a perfect sphere it actually is. Is curvature the right thing for this?
<anime> wow u must be so smart dalcde that sounded complicxed xD
<anime> i love pretending to be smart on the internet by talking about cohomology
<zehdeh> *in the area between the point and its neighbors
* cheeseboy has quit (Ping timeout: 240 seconds)
<dalcde> anime: Nah you need to find something harder.
<anime> dalcde, omg you're like sheldon out of big bang theory :D
<dalcde> Cohomology is easy. It is just computing the connected components of the hom sets with the nth delooping of the representing object in an infinity-1 topos.
<dalcde> (That is actually true)
dalcde!*@* added to ignore list.
<Svitkona> anime, can you please explain?
<FilipinosRich> Was about to say that the easy part is relative
<anime> stop pinging me
<Svitkona> anime, do you want me to stop pinging you?
<Svitkona> anime, was that towards me?
<xrlk> anime,
<FilipinosRich> anime why
<xrlk> were u talking about me??
<ayush1> rain1

Name: Anonymous 2016-08-08 18:25

>>48
turns out /prog/ is smarter than cambridge math teachers, who knew?
Nope. The problem is just too simple for them, so they make jokes out of you being stoopid. I.e. recommending you to "compute the third derived cohomology group of the stochastic bundle instead."

Name: Anonymous 2016-08-08 18:30

>>50
And that Svitkona simply uses ELIZA algorithm to troll you. So he is apparently very good at programming too, but just love to troll noobs and idiots.

Name: Anonymous 2016-08-08 21:32

>>48-49
why would you post this, do you think this represents a victory for you?

Name: Anonymous 2016-08-08 21:43

>>52
Yes. See >>4

Name: Anonymous 2016-08-08 21:50

what happened to /prog/? it's a completely different set of people now

we never used to have anyone like >>52

Name: Anonymous 2016-08-08 22:55

(this cohomology group left intentionally empty)

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